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GBase 8a数据库两个时间相差的秒数
GBase社区管理员发表于2020-09-01 12:40:3471次浏览0个评论
GBase 8a 数据库集群提供了timediff函数,返回2个时间相差的秒数。最大单位是小时。
gbase> select timediff('12:13:14.123456','13:14:15.234567');
+-----------------------------------------------+
| timediff('12:13:14.123456','13:14:15.234567') |
+-----------------------------------------------+
| -01:01:01.111111 |
+-----------------------------------------------+
1 row in set (Elapsed: 00:00:00.00)
gbase> select timediff('2020-01-02 12:13:14.123456','2020-01-03 13:14:15.234567');
+---------------------------------------------------------------------+
| timediff('2020-01-02 12:13:14.123456','2020-01-03 13:14:15.234567') |
+---------------------------------------------------------------------+
| -25:01:01.111111 |
+---------------------------------------------------------------------+
1 row in set (Elapsed: 00:00:00.00)
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